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16^2x+1=1/32
We move all terms to the left:
16^2x+1-(1/32)=0
We add all the numbers together, and all the variables
16^2x+1-(+1/32)=0
We get rid of parentheses
16^2x+1-1/32=0
We multiply all the terms by the denominator
16^2x*32-1+1*32=0
We add all the numbers together, and all the variables
16^2x*32+31=0
Wy multiply elements
512x^2+31=0
a = 512; b = 0; c = +31;
Δ = b2-4ac
Δ = 02-4·512·31
Δ = -63488
Delta is less than zero, so there is no solution for the equation
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